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Confused about relative complexity of longest increasing subsequence vs longest increasing subsequence (weighted by number of inversions)

I am having a tough time understanding the relative complexity of the two algorithms shown.
Link to problem explanation
Consider the first algorithm:
find(permutation, LIS)
initialise weight array (for all values of index i from 1 to n, store w[i] = i)
initialise current length (y) = 0
while y w[x] and w[j] – w[x] > 1:
w[j] = w[x] – 1
current = j
x = j
if w[x] > 0:
w[x] = 0
current = x + 1
current = w[x] – 1
y = current
yield(i)

If we run the algorithm on an array of 8 elements that is sorted, the output will be the two long increasing subsequences:
1
1 2
2
2 3
3
3 4
4 5
5

So, we found the 1st increasing subsequence: [1, 1, 2, 2, 3, 3, 4, 4, 5].
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