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In haskell, why does “map” and “let” parse the same things?
In Haskell, why does “map” and “let” parse the same things? Is it because “let” variables are local, but “map” variable exist in the global scope?
For example, if we write:
let addTwo x y = x + y
the second x is valid for addTwo. But if we write:
map (+) [1,2,3]
the second element in the list is invalid for the function. Why does Haskell let the second argument of map be valid in the first case, but not the second?
A:
in the first case, the map will first evaluate the addTwo function, by which time there is only a single x. By contrast, the let will just be in the function scope during the map (and the second argument is just a function with no body).
Note that the semantics of let do not require that the variables be not quantified in the binding, just that the binding occurs right away.
A:
In general, “map” can be written as a let:
map_let :: (a -> b) -> [a] -> [b]
map_let f [] = []
map_let f (x:xs) = f x :
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