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How does the + operator evaluate its first operand in a C expression?

I know that the second operator is just evaluating its operand like so:
(*(p+q))+7 = (*(p+q)+7)

I also have a decent understanding of how the + operator works in general (or to be specific the left-to-right associativity), which says that the operand to the right of the operator is evaluated first.
But where does the + operator get its operand evaluated? Is it evaluated from left to right?
This isn’t homework, but an exercise/question I encountered while writing a tiny interpreter.

A:

The answer is BASSIC, basic operator precedence.
Here’s how it’s done:
+ is the first operator evaluated. Then the second. Then the third (if any).
If this is not immediately obvious, how would you implement an arithmetic expression evaluator? A good first idea would be to just evaluate each expression in the order it is written in the source code, then apply the operators at each step.
So, the way it works:

a + b is evaluated.
a is evaluated.
The result of that evaluation is placed into a.
b is evaluated.
a + b, which is the result of step 2, is evaluated.
a is evaluated.
The result of that evaluation is placed into a.
The result of a is placed into b.
The result of a + b is placed into a.

Eliseo De Castro

Eliseo De Castro Arreza (1896 – September 1, 1937) was a Mexican businessman. He founded the El Azúcar beer company, which operated in Cuba until the 1950s. De Castro was also one of the founders of the Banco Nacional de Cuba in 1934.

Biography
Eliseo De Castro Arreza was born in the city of Celaya, Guanajuato, in 1896. He moved to Cuba in 1919 to establish an export business. That year, he bought a brewery in Santiago de Cuba. However, he fell into financial difficulties in 1929, which forced him to sell the brewery to American interests. That same year, he founded the beer company El Azúcar, which is still operating to this day
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